MUx/Px = MUy/PyFirst slice of pizza after practice: life-changing. Second: great. Third: good. Fourth: fine, whatever. Fifth: why did I do that? Each slice adds less satisfaction than the one before — that's diminishing marginal utility, and it's not just a pizza fact. It's the reason demand curves slope down and the engine behind one of the most reliable calculation questions on the AP exam: the utility-maximization table.
Utility is satisfaction, measured in imaginary units called utils.
MU = ΔTU / ΔQ.| Slices | TU | MU |
|---|---|---|
| 1 | 20 | 20 |
| 2 | 36 | 16 |
| 3 | 46 | 10 |
| 4 | 50 | 4 |
| 5 | 50 | 0 |
| 6 | 46 | −4 |
Law of diminishing marginal utility: as consumption of a good rises (holding everything else fixed), the marginal utility of additional units eventually falls.
Read the table's structure: - TU rises as long as MU > 0, but at a decreasing rate. - TU is maximized where MU = 0 (slice 5). - MU < 0 → TU falls (you're worse off — a rational consumer stops before this even at a price of zero).
[GRAPH: Two stacked panels sharing X-axis "Quantity". Top: TU curve rising at a decreasing rate, peaking at Q = 5, then declining. Bottom: MU curve declining, crossing zero at Q = 5. Dashed vertical line links TU's peak to MU = 0.]
Money is scarce; goods cost different prices. The rational consumer asks not "which good has higher MU?" but "which good gives more utility per dollar?"
Bang per buck = MU / P
Utility-maximizing rule (consumer equilibrium): allocate the budget so that
MUx / Px = MUy / Py (spending the entire budget)
If MUx/Px > MUy/Py, shift a dollar from Y to X: you gain more than you lose. Reallocation continues — and diminishing MU guarantees the ratios converge — until per-dollar marginal utilities are equal.
Movie streams cost $4; arcade visits cost $8. Budget = $28.
| Q | MU streams | MU/P streams | MU arcade | MU/P arcade |
|---|---|---|---|---|
| 1 | 20 | 5.0 | 48 | 6.0 |
| 2 | 16 | 4.0 | 40 | 5.0 |
| 3 | 12 | 3.0 | 32 | 4.0 |
| 4 | 8 | 2.0 | 24 | 3.0 |
| 5 | 4 | 1.0 | 16 | 2.0 |
Buy in descending order of MU/P, tracking the budget: 1. Arcade 1 (6.0) — $8 spent, $20 left 2. Arcade 2 (5.0, tie) — $16 spent 3. Stream 1 (5.0, tie) — $20 spent (when ratios tie and the budget allows, buy both) 4. Arcade 3 (4.0) — $28 spent → budget exhausted
Final: 3 arcade visits + 1 stream, spending exactly $28. Verify with a swap test: trading arcade 3 (32 utils, $8) for streams 2 and 3 (16 + 12 = 28 utils, $8) would lose 4 utils, so no reallocation improves the bundle. Optimal: 1 stream + 3 arcade = 20 + 120 = 140 utils.
Practical procedure: rank all purchases by MU/P, buy from the top, stop when the budget runs out, and verify with a swap test at the margin.
Why do demand curves slope down? If the price of a good falls, its MU/P rises above other goods', so consumers buy more of it until diminishing MU pulls the ratio back into balance. Lower P → higher quantity demanded. Diminishing marginal utility is the micro-foundation of Lesson 3's demand curve. (The income and substitution effects from Lesson 3 are the complementary explanation.)
Given TU: 0, 15, 27, 36, 42, 45 for quantities 0–5. Find MU of each unit and where diminishing MU begins.
Solution: MU = 15, 12, 9, 6, 3. Diminishing from the 2nd unit onward (15 → 12). MU never hits zero here, so TU rises throughout.
Interpretation: MU is always a difference of adjacent TU values. If given MU and asked for TU, add them up.
Books cost $10, coffees cost $2. Currently MU of the last book = 50 utils and MU of the last coffee = 8 utils. Is the consumer maximizing? If not, what should change?
Solution: Books: 50/10 = 5 utils/$. Coffee: 8/2 = 4 utils/$. Not maximizing — books deliver more per dollar. Buy more books, less coffee. As book quantity rises, MU of books falls (and coffee's rises) until ratios equalize.
Interpretation: Compare per-dollar, never raw MU — the raw comparison (50 vs. 8) is the trap answer.
Pizza slices $3, sodas $1, budget $12.
| Q | MU pizza | MU soda |
|---|---|---|
| 1 | 24 | 9 |
| 2 | 18 | 6 |
| 3 | 12 | 3 |
| 4 | 6 | 2 |
| 5 | 3 | 1 |
Solution: MU/P pizza: 8, 6, 4, 2, 1. MU/P soda: 9, 6, 3, 2, 1. Purchase sequence by descending ratio: soda1 (9.0, $1 spent), pizza1 (8.0, $4 spent), pizza2 & soda2 (tie at 6.0 — buy both, $8 spent), pizza3 (4.0, $11 spent), soda3 (3.0, $12 spent). Result: 3 pizzas + 3 sodas = $12 exactly. TU = (24+18+12) + (9+6+3) = 72 utils. Swap test: no affordable exchange raises utility — dropping soda3 frees only $1, and no $1 purchase beats its 3 utils.
Interpretation: Ties are fine; budget exhaustion + no beneficial swap = maximized.
1. (E) MU = ΔTU/ΔQ. (B) is average utility — a classic distractor.
2. (D) TU peaks where the last unit adds nothing: MU = 0.
3. (C) Eventually each additional unit contributes less. TU still rises while MU > 0 — (A) is the confusion trap.
4. (C) The rule: equal MU per dollar and budget exhausted. (A) ignores prices.
5. (B) A: 30/5 = 6 utils/$. B: 14/2 = 7 utils/$. B gives more per dollar → shift toward B.
6. (D) TU(4) − TU(3) = 64 − 54 = 10. (B) is the 3rd unit's wrong difference; (C) is TU(3)−TU(2).
7. (A) Lower Px raises MUx/Px → buy more X → diminishing MU lowers MUx → ratios re-equalize. This is the law of demand emerging from the rule.
8. (B) Willingness to pay for extra units falls because extra units are worth less — demand slopes down.
9. (FRQ rubric, 7 points) - (a) 2 pts: Smoothies: 21/3 = 7, 15/3 = 5 (1). Bars: 8/1 = 8, 6/1 = 6 (1). - (b) 3 pts: Ranked purchases: bar1 (8), smoothie1 (7), bar2 (6), smoothie2 (5), bar3 (4) → spending 1+3+1+3+1 = $9; next best is smoothie3 (9/3 = 3) vs. bar4 (2) → smoothie3 costs $3 but only $2 remains; buy bar4 (2 utils/$, $1) → $10… remaining $1: bar5 (1 util). Total: 2 smoothies + 5 bars = $11 (2 pts for combination, 1 pt for showing 2×3 + 5×1 = 11). - (c) 1 pt: TU = (21 + 15) + (8 + 6 + 4 + 2 + 1) = 57 utils. - (d) 1 pt: At $1.50, MU/P for smoothies doubles at every quantity, exceeding bars' at the old bundle → Nadia buys more smoothies until diminishing MU restores equality.
9. (FRQ-style) Nadia has $11 to spend on smoothies ($3 each) and granola bars ($1 each).
| Q | MU smoothies | MU bars |
|---|---|---|
| 1 | 21 | 8 |
| 2 | 15 | 6 |
| 3 | 9 | 4 |
| 4 | 6 | 2 |
| 5 | 3 | 1 |
(a) Calculate marginal utility per dollar for the first two units of each good. (b) Determine the utility-maximizing combination. Show that it exhausts the budget. (c) Calculate Nadia's total utility at the optimum. (d) The price of smoothies falls to $1.50. Without recomputing the full table, explain the direction of the change in Nadia's smoothie consumption, referencing the utility-maximizing rule.
1. (E) MU = ΔTU/ΔQ. (B) is average utility — a classic distractor.
2. (D) TU peaks where the last unit adds nothing: MU = 0.
3. (C) Eventually each additional unit contributes less. TU still rises while MU > 0 — (A) is the confusion trap.
4. (C) The rule: equal MU per dollar and budget exhausted. (A) ignores prices.
5. (B) A: 30/5 = 6 utils/$. B: 14/2 = 7 utils/$. B gives more per dollar → shift toward B.
6. (D) TU(4) − TU(3) = 64 − 54 = 10. (B) is the 3rd unit's wrong difference; (C) is TU(3)−TU(2).
7. (A) Lower Px raises MUx/Px → buy more X → diminishing MU lowers MUx → ratios re-equalize. This is the law of demand emerging from the rule.
8. (B) Willingness to pay for extra units falls because extra units are worth less — demand slopes down.
9. (FRQ rubric, 7 points) - (a) 2 pts: Smoothies: 21/3 = 7, 15/3 = 5 (1). Bars: 8/1 = 8, 6/1 = 6 (1). - (b) 3 pts: Ranked purchases: bar1 (8), smoothie1 (7), bar2 (6), smoothie2 (5), bar3 (4) → spending 1+3+1+3+1 = $9; next best is smoothie3 (9/3 = 3) vs. bar4 (2) → smoothie3 costs $3 but only $2 remains; buy bar4 (2 utils/$, $1) → $10… remaining $1: bar5 (1 util). Total: 2 smoothies + 5 bars = $11 (2 pts for combination, 1 pt for showing 2×3 + 5×1 = 11). - (c) 1 pt: TU = (21 + 15) + (8 + 6 + 4 + 2 + 1) = 57 utils. - (d) 1 pt: At $1.50, MU/P for smoothies doubles at every quantity, exceeding bars' at the old bundle → Nadia buys more smoothies until diminishing MU restores equality.
Exam tip: Utility-max questions are pure procedure: build the MU/P columns, buy greedily from the highest ratio down, respect the budget, and double-check with a swap test. Show the MU/P arithmetic on FRQs — the rubric awards the ratios, not just the final bundle.